Saraswati Vidyamandir Logo
Home Our Courses CBSE Resources
NCERT Solutions
Science — Class 9 Science — Class 10 About Us Contact Us Book Free Orientation
3

Atoms and Molecules

Class 9 Science  ·  NCERT Solutions  ·  23 Questions

23 Questions & Answers
Atoms and Molecules — NCERT Solutions. This chapter covers laws of chemical combination (conservation of mass and definite proportions), Dalton's atomic theory, atomic masses, molecules and their formulae, ions, chemical formulae, the mole concept, and Avogadro's number.
Q1

In a reaction, 5.3 g of sodium carbonate reacted with 6 g of acetic acid. The products were 2.2 g of carbon dioxide, 0.9 g of water and 8.2 g of sodium acetate. Show that these observations are in agreement with the law of conservation of mass.

Answer

The reaction is:

Na2CO3 + CH3COOH → CH3COONa + H2O + CO2

Mass of reactants:

Mass of sodium carbonate (Na2CO3) = 5.3 g

Mass of acetic acid (CH3COOH) = 6.0 g

Total mass of reactants = 5.3 + 6.0 = 11.3 g

Mass of products:

Mass of CO2 = 2.2 g

Mass of H2O = 0.9 g

Mass of sodium acetate (CH3COONa) = 8.2 g

Total mass of products = 2.2 + 0.9 + 8.2 = 11.3 g

Since mass of reactants = mass of products = 11.3 g, these observations are in agreement with the Law of Conservation of Mass, which states that matter is neither created nor destroyed in a chemical reaction.

Q2

Hydrogen and oxygen combine in the ratio of 1:8 by mass to form water. What mass of oxygen gas would be required to react completely with 3 g of hydrogen gas?

Answer

Given: H2 and O2 combine in the ratio 1 : 8 by mass to form water (H2O).

2H2 + O2 → 2H2O

This means 1 g of hydrogen requires 8 g of oxygen.

Therefore, 3 g of hydrogen will require:

Mass of O2 = 3 × 8 = 24 g

24 g of oxygen gas is required to react completely with 3 g of hydrogen gas.

Q3

Which postulate of Dalton's atomic theory is the result of the law of conservation of mass?

Answer

The following postulate of Dalton's atomic theory is the result of the law of conservation of mass:

"Atoms are indivisible particles which cannot be created or destroyed in a chemical reaction."

Since atoms are neither created nor destroyed, the total mass of atoms (and hence matter) remains the same before and after a chemical reaction. This is exactly what the law of conservation of mass states.

Q4

Which postulate of Dalton's atomic theory can explain the law of definite proportions?

Answer

The following postulate of Dalton's atomic theory explains the law of definite proportions:

"The relative number and kinds of atoms are constant in a given compound."

This means that any given chemical compound always contains the same elements combined in the same fixed ratio by number (and hence by mass). For example, water (H2O) always contains 2 hydrogen atoms for every 1 oxygen atom, regardless of how the water was produced or where it was obtained.

Q5

Define the atomic mass unit.

Answer

The atomic mass unit (u or amu) is defined as one-twelfth (1/12) of the mass of one atom of carbon-12 (12C).

1 u = (1/12) × mass of one carbon-12 atom = 1.66 × 10−24 g = 1.66 × 10−27 kg

The atomic mass unit provides a convenient scale for expressing the masses of atoms and molecules. For example, one atom of hydrogen has a mass of approximately 1 u, and one atom of oxygen has a mass of approximately 16 u.

Q6

Why is it not possible to see an atom with the naked eye?

Answer

It is not possible to see an atom with the naked eye because atoms are extremely small — their size is of the order of 10−10 m (0.1 nm or 1 Angstrom).

For comparison, the smallest object visible to the naked eye is about 0.1 mm (10−4 m), which is one million times larger than an atom.

Even the most powerful optical microscopes (which use visible light) cannot resolve individual atoms because the wavelength of visible light (~400–700 nm) is much larger than the size of an atom (~0.1 nm). According to the principles of optics, you cannot see objects smaller than the wavelength of light used to observe them.

Individual atoms can only be imaged using specialized instruments like the Scanning Tunnelling Microscope (STM) or Atomic Force Microscope (AFM), which work on quantum mechanical principles rather than visible light.

Q7

Write down the formulae for: (i) Sodium oxide   (ii) Aluminium chloride   (iii) Sodium sulphide   (iv) Magnesium hydroxide

Answer

To write the formulae, we use the valency (combining capacity) of each element/ion and apply the criss-cross method:

(i) Sodium oxide — Na+1 and O−2

Na2O

(ii) Aluminium chloride — Al+3 and Cl−1

AlCl3

(iii) Sodium sulphide — Na+1 and S−2

Na2S

(iv) Magnesium hydroxide — Mg+2 and OH−1

Mg(OH)2
Q8

Write down the names of compounds represented by the following formulae: (i) Al2(SO4)3   (ii) CaCl2   (iii) K2SO4   (iv) KNO3   (v) CaCO3

Answer

(i) Al2(SO4)3Aluminium sulphate

(ii) CaCl2Calcium chloride

(iii) K2SO4Potassium sulphate

(iv) KNO3Potassium nitrate

(v) CaCO3Calcium carbonate

Q9

What is meant by the term chemical formula?

Answer

A chemical formula is a symbolic representation of the composition of a compound (or element). It shows:

1. The types of atoms (elements) present in the compound.

2. The number of atoms of each element in one molecule (or formula unit) of the compound.

Examples:

H2O — One molecule of water contains 2 hydrogen atoms and 1 oxygen atom.

CO2 — One molecule of carbon dioxide contains 1 carbon atom and 2 oxygen atoms.

NaCl — One formula unit of common salt contains 1 sodium ion and 1 chloride ion.

H2SO4 — One molecule of sulphuric acid contains 2 hydrogen, 1 sulphur, and 4 oxygen atoms.

The chemical formula also allows us to calculate the molecular mass of a compound by adding the atomic masses of all atoms present.

Q10

How many atoms are present in a molecule of: (i) H2S   (ii) PO43−

Answer

(i) H2S (Hydrogen sulphide):

Number of hydrogen atoms = 2

Number of sulphur atoms = 1

Total atoms = 2 + 1 = 3 atoms

(ii) PO43− (Phosphate ion):

Number of phosphorus atoms = 1

Number of oxygen atoms = 4

Total atoms = 1 + 4 = 5 atoms

Q11

Calculate the molecular masses of: H2, O2, Cl2, CO2, CH4, C2H6, C2H4, NH3, CH3OH.
(Atomic masses: H=1, C=12, N=14, O=16, Cl=35.5)

Answer

H2 (Hydrogen): 2 × 1 = 2 u

O2 (Oxygen): 2 × 16 = 32 u

Cl2 (Chlorine): 2 × 35.5 = 71 u

CO2 (Carbon dioxide): 12 + (2 × 16) = 12 + 32 = 44 u

CH4 (Methane): 12 + (4 × 1) = 12 + 4 = 16 u

C2H6 (Ethane): (2 × 12) + (6 × 1) = 24 + 6 = 30 u

C2H4 (Ethene): (2 × 12) + (4 × 1) = 24 + 4 = 28 u

NH3 (Ammonia): 14 + (3 × 1) = 14 + 3 = 17 u

CH3OH (Methanol): 12 + (3 × 1) + 16 + 1 = 12 + 3 + 16 + 1 = 32 u

Q12

Calculate the formula unit masses of ZnO, Na2O, K2CO3.
(Atomic masses: Zn=65, Na=23, K=39, C=12, O=16)

Answer

ZnO (Zinc oxide):

Zn + O = 65 + 16 = 81 u

Na2O (Sodium oxide):

(2 × Na) + O = (2 × 23) + 16 = 46 + 16 = 62 u

K2CO3 (Potassium carbonate):

(2 × K) + C + (3 × O) = (2 × 39) + 12 + (3 × 16) = 78 + 12 + 48 = 138 u
Q13

If one mole of carbon atoms weighs 12 grams, what is the mass (in grams) of 1 atom of carbon?

Answer

Given:

Mass of 1 mole of carbon atoms = 12 g

1 mole contains Avogadro's number of atoms = 6.022 × 1023 atoms

Mass of 1 atom of carbon = 12 g ÷ (6.022 × 1023)
= 1.993 × 10−23 g ≈ 2 × 10−23 g

The mass of one carbon atom is approximately 1.993 × 10−23 g.

Q14

Which has more number of atoms, 100 grams of sodium or 100 grams of iron? (Atomic masses: Na = 23 u; Fe = 56 u)

Answer

For Sodium (Na):

Moles of Na = Mass / Molar mass = 100 / 23 = 4.34 mol

Number of atoms of Na = 4.34 × 6.022 × 1023 = 2.61 × 1024 atoms

For Iron (Fe):

Moles of Fe = Mass / Molar mass = 100 / 56 = 1.786 mol

Number of atoms of Fe = 1.786 × 6.022 × 1023 = 1.075 × 1024 atoms

Since 2.61 × 1024 > 1.075 × 1024, 100 grams of sodium has more atoms than 100 grams of iron.

This is because sodium has a smaller atomic mass (23 u) compared to iron (56 u), so for the same mass, there are more moles (and hence more atoms) of sodium.

Q15

A 0.24 g sample of a compound of oxygen and boron was found by analysis to contain 0.096 g of boron and 0.144 g of oxygen. Calculate the percentage composition of the compound by weight.

Answer

Total mass of sample = 0.24 g

Mass of boron = 0.096 g

Mass of oxygen = 0.144 g

% of Boron = (mass of boron / total mass) × 100 = (0.096 / 0.24) × 100 = 40%
% of Oxygen = (mass of oxygen / total mass) × 100 = (0.144 / 0.24) × 100 = 60%

The compound contains 40% Boron and 60% Oxygen by weight. Total = 40 + 60 = 100% (verified).

Q16

State the law of conservation of mass. Give one example.

Answer

The Law of Conservation of Mass states: "In any physical or chemical change, matter is neither created nor destroyed; the total mass of the reactants is equal to the total mass of the products."

This law was given by Antoine Lavoisier in 1774.

Example: When hydrogen gas reacts with oxygen gas to form water:

2H2 (g) + O2 (g) → 2H2O (l)

4 g of H2 + 32 g of O2 = 36 g of H2O. The total mass before (36 g) equals the total mass after (36 g), confirming conservation of mass.

Q17

State the law of definite proportions. Give one example.

Answer

The Law of Definite Proportions (or Law of Constant Proportions) states: "In a chemical compound, elements are always present in definite proportions by mass, regardless of the source or method of preparation of the compound."

This law was given by Joseph Louis Proust in 1799.

Example: Water (H2O) always contains hydrogen and oxygen in the mass ratio of 1:8.

Whether water is obtained from a river, formed by the combustion of hydrogen, or produced by any other method, it always contains:

Mass of H : Mass of O = 2 : 16 = 1 : 8

This ratio never changes, illustrating the law of definite proportions.

Q18

What is the mole concept? What is Avogadro's number?

Answer

The mole is the SI unit for the amount of substance. One mole of any substance contains the same number of particles (atoms, molecules, ions, etc.) as there are atoms in exactly 12 grams of carbon-12.

Avogadro's Number (NA): The number of particles in one mole of any substance is called Avogadro's number.

NA = 6.022 × 1023 per mole

Key relationships of the mole concept:

1. 1 mole of atoms = 6.022 × 1023 atoms = molar mass of the element (in grams)

2. 1 mole of molecules = 6.022 × 1023 molecules = molecular mass (in grams)

3. 1 mole of a gas at STP = 22.4 litres (molar volume)

Examples: 1 mole of H2O = 18 g of water = 6.022 × 1023 molecules of water. 1 mole of NaCl = 58.5 g of salt.

Q19

Calculate the number of moles in 52 g of He (Helium) and in 12.044 × 1023 atoms of He.

Answer

Atomic mass of He = 4 u, so molar mass of He = 4 g/mol.

Part 1 — From mass:

Moles of He = mass / molar mass = 52 / 4 = 13 moles

Part 2 — From number of atoms:

Moles of He = (number of atoms) / NA = (12.044 × 1023) / (6.022 × 1023) = 2 moles
Q20

Calculate the mass of: (a) 0.5 mole of N2 gas   (b) 0.5 mole of N atoms   (c) 3.011 × 1023 atoms of N   (d) 6.022 × 1023 molecules of N2

Answer

Atomic mass of N = 14 u; Molar mass of N2 = 28 g/mol; Molar mass of N (atom) = 14 g/mol.

(a) 0.5 mole of N2:

Mass = 0.5 × 28 = 14 g

(b) 0.5 mole of N atoms:

Mass = 0.5 × 14 = 7 g

(c) 3.011 × 1023 atoms of N:

Moles = (3.011 × 1023) / (6.022 × 1023) = 0.5 mol; Mass = 0.5 × 14 = 7 g

(d) 6.022 × 1023 molecules of N2:

Moles = (6.022 × 1023) / (6.022 × 1023) = 1 mol; Mass = 1 × 28 = 28 g
Q21

What is meant by a polyatomic ion? Give three examples with their formulae and charges.

Answer

A polyatomic ion is a charged species (ion) that consists of two or more atoms covalently bonded together, carrying an overall positive or negative charge. They behave as a single unit in ionic compounds.

Examples:

(i) Sulphate ion: SO42− — 1 sulphur atom + 4 oxygen atoms; charge = −2

(ii) Nitrate ion: NO3 — 1 nitrogen atom + 3 oxygen atoms; charge = −1

(iii) Ammonium ion: NH4+ — 1 nitrogen atom + 4 hydrogen atoms; charge = +1

(iv) Carbonate ion: CO32− — 1 carbon atom + 3 oxygen atoms; charge = −2

Q22

Write the chemical formulae for the following compounds: (i) Magnesium chloride, (ii) Calcium oxide, (iii) Copper nitrate, (iv) Aluminium chloride, (v) Calcium carbonate.

Answer

(i) Magnesium chloride: Mg2+ and Cl

MgCl2

(ii) Calcium oxide: Ca2+ and O2−

CaO

(iii) Copper nitrate: Cu2+ and NO3

Cu(NO3)2

(iv) Aluminium chloride: Al3+ and Cl

AlCl3

(v) Calcium carbonate: Ca2+ and CO32−

CaCO3
Q23

What are ions? Distinguish between cations and anions with examples.

Answer

Ions are electrically charged atoms or groups of atoms. An ion is formed when an atom (or group of atoms) gains or loses one or more electrons.

Cation (Positive Ion):

Formed when an atom loses one or more electrons. It carries a positive charge.

Examples:

Na+ (sodium ion) — Na loses 1 electron

Ca2+ (calcium ion) — Ca loses 2 electrons

Al3+ (aluminium ion) — Al loses 3 electrons

NH4+ (ammonium ion) — a polyatomic cation

Anion (Negative Ion):

Formed when an atom gains one or more electrons. It carries a negative charge.

Examples:

Cl (chloride ion) — Cl gains 1 electron

O2− (oxide ion) — O gains 2 electrons

S2− (sulphide ion) — S gains 2 electrons

SO42− (sulphate ion) — a polyatomic anion